三角形ＡＢＣ中，角Ｃ＝９０度，ＡＣ＝８＊根號５，角Ａ的平分線ＡＤ＝１６＊根號１５／３，（１）求作以直角三角形ＡＢＣ兩銳角的正弦值為根的一元二次方程；（２）求三角形ＡＢＣ面積

熱心網友

提示：　　由AC＝8√5　、AD＝（16√5)/3 得∠CAD＝30°所以∠CAD＝60°、∠B＝30°

熱心網友

hello:i think you are not a good student !you should do it by yourself!you can do it !it's not very difficulty!good luck to you ！

熱心網友

你偷懶把,自己好好做作業