另一設Cn=An/2的N次方,求Cn是等差數列

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數列An的前N+1項和=4An+2,A1=1,設Bn=A(n+1)求數列Bn為等比數列Sn+1=4An+2Sn=4An+1Sn+1-Sn=4(An+2 -An+1)=An+1所以An+2=5A(n+1)/4 An=(5/4)^(n-1)Bn=A(n+1)=(5/4)^n為等比數列設Cn=An/2^n,求Cn是等差數列Cn=(5/4)^(n-1)/2^nCn+1=(5/4)^n/2^(n+1)Cn+1/Cn =5/8Cn是等比數列