求導(dǎo)數(shù)

熱心網(wǎng)友

y=ln[x+√(1+x^2)]y'=[x+√(1+x^2)]'/[x+√(1+x^2)]={1+[(1+x^2)'/2√(1+x^2)]}/[x+√(1+x^2)]={1+[2x/2√(1+x^2)]}/[x+√(1+x^2)]=1/√(1+x^2)