已知數列{an}的前n項和為Sn ,Sn=(1/3)(An-1) ,(n∈ N*) 求a1 ,a2.

熱心網友

a1 = S1 = (1/3)(a1 - 1) == a1 = -1/2a1 + a2 = S2 = (1/3)(a2 - 1) == a2 = 1/4