實驗室要配制360.0克10%的鹽酸，需要36%的濃鹽酸（密度：1.2g/cm3)_______ml;水——ml.（水的密度為1.0g/cm3）.請寫出具體過程?？?。thanks.

熱心網(wǎng)友

M鹽酸=360g*10%/36%=100gV鹽酸=100g/1。2g/cm3=83。3mlM水=360g*（1-10%）=324gV水總=324g/1g/cm3=324mlV水加=324ml-（83。3ml*36%）=294。012ml

熱心網(wǎng)友

解：M鹽酸=360g*10%/36%=100g V鹽酸=100g/1。2g/cm3=83。3ml M水=360g*（1-10%）=324g V水總=324g/1g/cm3=324ml V水加=324ml-（83。3ml*36%）=294。012ml答：……