已知奇函數(shù)f(x)在x不等于０上有意義，且在x>0上是增函數(shù)，f(1)=0又有函數(shù)g(@)=(sin@)^ ,@屬于［０，pai/2].若集合M={m/g(@）<0},集合Ｎ＝｛m/f(g(@))<0}求f(x)<0的解；Ｍ交Ｎ．

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已知奇函數(shù)f(x)在x不等于０上有意義，且在x0上是增函數(shù)，f(1)=0又有函數(shù)g(@)=(sin@)^ ,@屬于［０，pai/2].若集合M={m/g(@）0上是增函數(shù),f(1)=0.所以f(0)=-f(0),即f(0)=0,并且由奇函數(shù)的性質(zhì)知:f(x)在x[(sin@)^2+1]/(2-cos@),@∈[0,pai/2]}