請寫過程式。謝謝

熱心網(wǎng)友

解:f(x)=0,三根是x1<x2<x3①a>0∵當(dāng)x>x3時,f(x)a(x-x1)(x-x2)(x-x3)>0說明a>0.②b<0∵f(x)=a(x-x1)(x-x2)(x-x3)=ax^3-a(x1+x2+x3)x^2+......b=-a(x1+x2+x3)∵a>0,x1+x2+x3>0[注:若x1=0,x2=1,x3=2,顯然x1+x2+x3=3>0]∴b<0