已知P為AB上一點(diǎn)，且AP^2=BP×AB，則BP/AP=__________需要詳解
熱心網(wǎng)友
AP^2=BP×AB=(AB-AP)×ABAP=(√5-1)AB/2BP=AB-AP=AB-(√5-1)AB/2=(3√5-1)AB/2BP/AP=(√5-1)/2
已知P為AB上一點(diǎn)，且AP^2=BP×AB，則BP/AP=__________需要詳解
AP^2=BP×AB=(AB-AP)×ABAP=(√5-1)AB/2BP=AB-AP=AB-(√5-1)AB/2=(3√5-1)AB/2BP/AP=(√5-1)/2