若函數(shù)y=Asin(ωx+c)(A>0,ω>0,0<c<2派)的最小值為-2周期為2派/3且他的圖象過點(diǎn)(0,-根號(hào)2)求解析試

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y=Asin(ωx+c)(A0,ω0,0 A = 2周期為2派/3 == ω = 3-根號(hào)2 = 2*sin(3*0 + c) == c = 5*派/4或7*派/4因此, y = 2*sin(3x + 5*派/4) = -2*sin(3x + 派/4)或: y = 2*sin(3x + 7*派/4) = 2*sin(3x - 派/4)