設X大于1，則函數Y=2X+X-1分之8有最小值是-----

熱心網友

Y=2X+8/(X-1)=2X+16/2(X-1)=2(X-1)+16/2(X-1)+2≥2√2(x-1)*16/2(X-1) +2≥8+2=10

熱心網友

函數Y=2X+8/(X-1)=2X+16/2(X-1)=2(X-1)+16/2(X-1)+2≥2√2(x-1)*16/2(X-1) +2≥8+2=10(X大于1,當且僅當2(x-1)=16/2(X-1)即x=3時取等號)則函數Y=2X+X-1分之8有最小值是-----10