請(qǐng)寫出過程

熱心網(wǎng)友

x^2-xy-2y^2-x-y=x^2-xy-y^2-y^2-x-y=(x-y)(x+y)-y(x+y)-(x+y)=(x+y)(x-2y-1)

熱心網(wǎng)友

把原式按照x的降冪排列，得到原式=x^2-(y+1)x-y(2y+1)【顯然有(-2y-1)+y=-y-1。】 =(x-2y-1)(x+y)

熱心網(wǎng)友

x^2-xy-2y^2-x-y=x^2-xy-y^2-y^2-x-y=(x-y)(x+y)-y(x+y)-(x+y)=(x+y)(x-2y-1)

熱心網(wǎng)友

x²-xy-2y²-x-y=x²-xy-y²-y²-x-y=(x-y)(x+y)-y(x+y)-(x+y)=(x+y)(x-2y-1)

熱心網(wǎng)友

原式=(x+y)(x-2y)-(x+y)=(x+y)(x-2y-1)

熱心網(wǎng)友

我想你應(yīng)該是個(gè)初中生吧，那么樓上的回答都是正確的，如果你是個(gè)高中生的話，類似的問題，不用分解因試，直接用導(dǎo)數(shù)就可以了

熱心網(wǎng)友

X^2－XY－2Y^2－X－Y=(X^2－XY－2Y^2)－(X＋Y)=(X－2Y)(X＋Y)－(X＋Y)=(X＋Y)(X－2Y－1)

熱心網(wǎng)友

x平方-xy-2y平方-x-y= x平方-xy-y平方-x-y-y平方=(x平方-y平方)-(y平方+xy)-(x+y)=(x+y)(x-y)-y(x+y) -(x+y)=(x+y)(x-2y-1)

熱心網(wǎng)友

x^2-xy-2y^2-x-y=x^2-xy-y^2-y^2-x-y=(x-y)(x+y)-y(x+y)-(x+y)=(x+y)(x-2y-1)