若不等式2x-1>m(x^2-1)對滿足-2<=x<=2的所有實數m都成立，則實數x的取值范圍麻煩各位幫忙解答，謝謝
2x-1m(x^2-1)等價于mx^2-x+(1-m)=0---(3m-3)(3m+5)=0----5/3=
