甲乙兩倉共245T大米,甲運出1/4,乙運出1/5后,兩倉共剩190T大米,甲乙各有多少T大米?
熱心網友
設甲倉有xt大米,所以乙倉有(245-x)t大米,可列245-(1/4)x-(1/5)(245-x)=190解得:x=120t,245-x=125t故甲倉有120t ,乙倉有125t
熱心網友
設甲為xT大米,則乙有245-x T大米 (1/4)x+(1/5)(245-x)=245-190 解得:x=120 245-120=125 故甲有120 T,乙有125 T
甲乙兩倉共245T大米,甲運出1/4,乙運出1/5后,兩倉共剩190T大米,甲乙各有多少T大米?
設甲倉有xt大米,所以乙倉有(245-x)t大米,可列245-(1/4)x-(1/5)(245-x)=190解得:x=120t,245-x=125t故甲倉有120t ,乙倉有125t
設甲為xT大米,則乙有245-x T大米 (1/4)x+(1/5)(245-x)=245-190 解得:x=120 245-120=125 故甲有120 T,乙有125 T