已知2^(6a)=3^(3b)=6^(2c),(abc不等于0), 則1/(6a)+1/(3b)-1/(2c)=?
熱心網(wǎng)友
2^(6a)=3^(3b)=6^(2c)兩邊取對數(shù),則6alg2=3blg3=2clg6所以6alg2+3blg3=4c(lg2+lg3) 所以6a=4c,3b=4c1/(6a)+1/(3b)-1/(2c)=0
已知2^(6a)=3^(3b)=6^(2c),(abc不等于0), 則1/(6a)+1/(3b)-1/(2c)=?
2^(6a)=3^(3b)=6^(2c)兩邊取對數(shù),則6alg2=3blg3=2clg6所以6alg2+3blg3=4c(lg2+lg3) 所以6a=4c,3b=4c1/(6a)+1/(3b)-1/(2c)=0