已知直線系L1: ax-ky+k=0, L2: kx-y-1=0,a為常數(shù),k為參數(shù) ,L1與L2交點(diǎn)的軌跡方程是??

熱心網(wǎng)友

L1: ax-ky+k=0, L2: kx-y-1=0,消去參數(shù)k: 得: aX^2 = Y^2 -1此即為L(zhǎng)1與L2交點(diǎn)的軌跡方程

熱心網(wǎng)友

看過這題頭暈！走了！

熱心網(wǎng)友

列方程組,求出交點(diǎn)出交點(diǎn) x=..... y=.....消去參數(shù)k既可

熱心網(wǎng)友

已知直線系L1: ax-ky+k=0, L2: kx-y-1=0,a為常數(shù),k為參數(shù) ,L1與L2交點(diǎn)的軌跡方程是??解：求交點(diǎn)：，由ax-ky+k=0, kx-y-1=0,得x=(2k)/(k^2-a),y=(k^2+a)/(k^2-a)